Physics, asked by DeekshaThangadurai, 11 months ago

A body starts accelerating from rest under gravity. What is the displacement of the body in the time interval of 10-15 seconds? (Assume g = 10 m/s^2)​

Answers

Answered by Manish6264744274
42

Explanation:

HEY MATE

HERE IS YOUR ANSWER

ACCORDING TO NEWTON 2ND EQUATION

S=UT+1/2 AT²

as initial speed is 0

for time 10 sec

S=0(10)+1/2 g (10)²

S=1/2 ×10×100

S=500m

FOR 15 SEC

S=0(10)+1/2 10 (15)²

S=5×225

S= 1125m

for DISPLACEMENT

s2-s1

1125-500

625 is the net DISPLACEMENT by the body

hope help you

thanks

Answered by Atmanshprakash
0

Answer:

625

Explanation:

ACCORDING TO NEWTON 2ND

EQUATION

S = UT + 1/2 * A * T ^ 2

as initial speed is 0

for time 10 sec

S = O(10) + 1/2 * g * (10) ^ 2

S = 1/2 * 10 * 100

S = 500m

FOR 15 SEC

S = O(10) + 1/2 10 (15)²

S = 5 * 225

S = 1125m

for DISPLACEMENT

s2-s1

1125-500

625 is the net DISPLACEMENT by the

body

hope it helped you

thanks

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