A body starts accelerating from rest under gravity. What is the displacement of the body in the time interval of 10-15 seconds? (Assume g = 10 m/s^2)
Answers
Answered by
42
Explanation:
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HERE IS YOUR ANSWER
ACCORDING TO NEWTON 2ND EQUATION
S=UT+1/2 AT²
as initial speed is 0
for time 10 sec
S=0(10)+1/2 g (10)²
S=1/2 ×10×100
S=500m
FOR 15 SEC
S=0(10)+1/2 10 (15)²
S=5×225
S= 1125m
for DISPLACEMENT
s2-s1
1125-500
625 is the net DISPLACEMENT by the body
hope help you
thanks
Answered by
0
Answer:
625
Explanation:
ACCORDING TO NEWTON 2ND
EQUATION
S = UT + 1/2 * A * T ^ 2
as initial speed is 0
for time 10 sec
S = O(10) + 1/2 * g * (10) ^ 2
S = 1/2 * 10 * 100
S = 500m
FOR 15 SEC
S = O(10) + 1/2 10 (15)²
S = 5 * 225
S = 1125m
for DISPLACEMENT
s2-s1
1125-500
625 is the net DISPLACEMENT by the
body
hope it helped you
thanks
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