Question

A body starts from A and moves according to given figure. Time for each interval is: (t^ab = 2s, t^bc = 3s, t^cb = 3s, t^ad = 4s). Than find the distance, displacement, speed, and velocity for each path .

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Answer 1

Answer:

Explanation:

for a-b path,

distance = 4m

displacement = +4m

time = 2sec

so, speed = 2m/s

velocity = +2m/s

for b-c path,

distance = 6m

displacement = +6m

time = 3 sec

so speed = 2m/s

velocity = +2m/s

for a-d path,

distance = 5m

displacement = -5m (opposite in direction, so a minus sign)

time = 4 sec

so, velocity =  -5/4 = -1.25 m/s (since displacement is negative)

speed = 1.25m/s

Answer 2

Explanation:

distance AB = 4 m

Displacement AB = 4m

speed AB = 4/2 = 2m/s

velocity AB = 2m/s

distance AC = 10 m

Displacement AC= 10m

speed AC = 10/5 = 2m/s

velocity AC = 2m/s

distance A to C and C to B = 4+6+6= 16m

Displacement A to C and C to B =4+6- 6m = 4m

speed A to C and C to B = 16/8 = 2m/s

velocity A to C and C to B = 4/8 = 0.5 m/s

distance A to C and C to B and B to A = 4+6+6+4= 20m

Displacement A to C and C to B =4+6-6-4 = 0

speed A to C and C to B = 20/10 = 2m/s

velocity A to C and C to B = 0/8 = 0

distance A_C and C_B and B_A and A_D= 20+5=25m

Displacement A_C and C_B and B_A and A_D = -5m

speed A_C and C_B and B_A and A_D = 25/14 = 1.78 m/s

velocity A_C and C_B and B_A and A_D = 5/14 = 0.14m/s