A body starts from origin moves along the x axis such that the velocity at any instant is given by( 4t^3-2t) .what is the acceleration of the particle when it is at a distance 2 meter from the origin?
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6
v = 4t^3 - 2t
for acceleration ,
dv/dt = a
a= 12t^2 -2. ............(1)
and by integrating equation v we get ,
x = t^4 - t^2...........(2)
substituting value of x in above equation,
t^4 - t^2 - 2 = 0
t = √2 seconds
substituting value of t in equation (1)
a = 12×2 -2
a = 22 m per second square.........answer
for acceleration ,
dv/dt = a
a= 12t^2 -2. ............(1)
and by integrating equation v we get ,
x = t^4 - t^2...........(2)
substituting value of x in above equation,
t^4 - t^2 - 2 = 0
t = √2 seconds
substituting value of t in equation (1)
a = 12×2 -2
a = 22 m per second square.........answer
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3
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