Question

A body starts from point A with an initial velocity of 2 ms-1 and
with a constant acceleration of 5/2ms-2. How much distance would
it have travelled when the velocity has reached 10 ms-1?​

Answer 1

V=U+at

10=2+5/2*t

10-5/2-2=t

t=11/2=5.5 second

s=ut+at^2

s=2*5.5+2.5*5.5^2

s=11+2.5*30.25

s=86.626

distance=86.625