A body starts from rest accelerate uniformly at the rate of 5m/s2
for 10 sec. Find the
distance travel by the body?
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mahakkukkar:
you're welcome
i have a mistake
i have written by using 1st eqn of motion
it will be 2nd
ok
Always first analyse the question and the given data....And then think of any other thing
is it incorrect
acc. to me it is correct
if you feel it may be wrong you may consult any friend
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Answered by
4
initial velocity = 0m/s
acceleration= 5m/s^2
time taken = 10s
distance travelled= ?
by using the formula:
s= ut+1/2at^2
s= 0*10+1/2*5*(10)^2
s= 0+1/2*5*100
s= 5*50
s= 250m
therefore distance travelled by an object is 250m.
hope it will help u
acceleration= 5m/s^2
time taken = 10s
distance travelled= ?
by using the formula:
s= ut+1/2at^2
s= 0*10+1/2*5*(10)^2
s= 0+1/2*5*100
s= 5*50
s= 250m
therefore distance travelled by an object is 250m.
hope it will help u
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