Question

A body starts from rest acquires a velocity of 15m/s in 5s .If mass of body is 4kg then find Force acting on it.


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Answer 1

Answer:

Force acting on the body is 15N

Explanation:

Given that, A body of mass 4kg initially at rest and attains a velocity of 15m/s in 5s.

Find the force acting on it.

Force acting on it is given by :-

→ Mass × Acceleration

We know,

→ Acceleration = change in velocity/time taken.

Here,

The body's was at rest so, it goes from 0m/s to 15m/s.

Then,

→ 15 - 0/5

→ 15/5

→ 3m/s

Now, calculating the force acting on it :-

→ F = mass × acceleration

Where,

• mass = 5kg
• acceleration = 3m/s

So,

→ F = 5*3

→ F = 15N

∴ Force acting on the body is 15N.

_____________________

Note :

Change in velocity is the difference of final velocity by initial velocity.

Formula used :

• Acceleration = change in velocity/time taken
• Force = mass × acceleration.

S. I. Units :

• Acceleration = m/s
• Force = N(Newton)
• mass = kg.

Answer 2

Answer:

Initial momentum $$p=mu\ \ m=50\ kg,

$$=50\ kg \times 0=0\ u=0,

Final momentum p=mv   v=15 m/s,

=50 kg×15 m/s t=10 sec

=750 kg m/s

Change in momentum =mv−mv

=750 kg m/s−0

=750 kg m/s

Rate change of momentum

=tmv−mu=10 s750 kg m/s=75 kg m/s2



Answer verified by Toppr

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