A body starts from rest & move with uniform acceleration of 4m/s².how much time will it takes to cover a distance of 128m?
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Answer: 0.8 seconds
Explanation: Initial velocity = 0 m/2
Acceleration = 4 m/s^2
distance = 128 cm = 0.128 m
using the equation d = Vi * t + (1/2) *a*t^2
since Vi = 0 , the term Vi * t = 0
therefore:
d = (1/2)at^2
rearranged for time:
square root of (2d)/a = square root of [(0.256m)/(4m/s^2)]
= sqrt 0.64
= 0.8 seconds ( answer )
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