A body starts from rest and accelerates by 9 m/s2. Find velocity and distance covered by the body after 2seconds.
please tell the answer with the solving.
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Explanation:
u=0
a=9m/s²
t=2sec
since we know that
v = u+at
v = 0+ 9×2
v = 18m/s
By Third law of Motion
s = ut +1/2at²
s = 0×2 + 1/2 ×9 ×(2)²
s = 1/2×9×4
s = 18m
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