Question

A body starts from rest and acquires a velocity of 12m/s in 5 second calculate acceleration and distance moved​

Answer 1

Mark as the brainliest answer

Answer 2

Given

• Initial velocity (u) = 0 m/s
• Final velocity (v) = 12 m/s
• Time taken (t) = 5 seconds

To find

• Acceleration (a)
• Distance (s)

Solution

First law of motion :-

• v = u + at

⇾ 12 = 0 + a(5)

⇾ 12 = 5a

⇾ a = ¹²⁄₅

⇾ a = 2.4

Acceleration of the body is 2.4 m/s

Second law of motion :-

• s = ut + ½at²

⇾ s = 0(5) + ½(2.4)(5)²

⇾ s = ½ × 2.4 × 25

⇾ s = 1.2 × 25

⇾ s = 30

Distance covered by body is 30 m