Question

A body starts from rest and acquires a velocity of 12m/s in 5 second calculate acceleration and distance moved​

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class 8

Answer 1

v = u + at

⇾ 12 = 0 + a(5)

⇾ 12 = 5a

⇾ a = ¹²⁄₅

⇾ a = 2.4

Acceleration of the body is 2.4 m/s

Second law of motion :-

s = ut + ½at²

⇾ s = 0(5) + ½(2.4)(5)²

⇾ s = ½ × 2.4 × 25

⇾ s = 1.2 × 25

⇾ s = 30

Distance covered by body is 30 m

Answer 2

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Initial velocity, u = 0

Final velocity, v = 12m/s

Time taken to acquire the velocity, t = 5s

Using the equation, we have

v = u + at

(NOW HERE REFER THE ATTACHMENT)

where, a is the acceleration of the moving car,

and

s is the distance moved by the car.