Question

A body starts from rest and acquires a velocity of 12mper second in 5seconds then the acceleration and the distance travelled are

Answer 1

u=0
v= 12m/s
t= 5sec
a=?
s=?

v=u+at
at= 12
a= 12/5= 2.4m/s^2

s=ut+1/2at^2
s= 1/2at^2
s= 1.2x25
s=30m

Answer 2

Soln: From the data given in the problem we have,

Initial velocity = u =0,

final velocity v=20 m/sec,

Time of journey t=4sec,

Acceleration a =  = = 5 

Displacement S = ut +  = 0 (4)+

S = 40m.