Question

a body starts from rest and acquires a velocity of 36 km/h after 3 sec when a force is applied on it in 3 sec.calculate the distance covered by it in 3 sec with explanation​

Answer 1

initial velocity = 36 km/h

= 20 m/s

final velocity=0 m/s

time =. 3s

using eqn 1

v=u+at

-20=3aa=20/3

putting in eqn 3

v²-u²=2as

400= 2×20/3×s

s= 30 m