Physics, asked by rithikareddy5115, 4 months ago

A body starts from rest And attains a speed of 4m/s in 5seconds. Find the acceleration of the body.

Answers

Answered by RB26DETT
0

Answer:

A= 0.8 m/s^2

Explanation:

A= v-u/t

4-0/5

= 0.8 m/s^2

Hope you understand it.

Answered by harisreeps
0

Answer:

A body moving with a velocity of 4m/s is brought to rest in 5seconds, its acceleration is 0.8m/s^{2}

Explanation:

  • We know the equation of motion

       V=u+at

where,

V- the final velocity

u- the initial velocity

a- acceleration of the body

t- time to change the velocity

S- distance moved

  • The acceleration is the change in velocity divided by time

using the first equation of motion acceleration of the body is

a=\frac{V-u}{t}

from the question, we have

the initial velocity u=4m/s

the body brought to rest so

the final velocity V= 0

the time taken t=5s

therefore the acceleration a=\frac{0-4}{5} =-4/5=-0.8m/s^{2}

the negative sign is due to retardation

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