Question

A body starts from rest and attains the velocity of 18m/s in 6 seconds .Find tge displacement after 12 seconds

Answer 1

v= u + at.

or 18= 0+ a*6
or a= 18/6= 3 m/ s²

also total displacement (s)= ut + ½at²


= ½*3*12*12

= 18*12

= 216meter

hope this makes u understand

Answer 2

Hii Friend

Good morning

lets us solve this problem

Q=easy

Starting velocity(u)=0(started from rest)

Final velocity (v)(=18m/s

Time=6sec

use 1st equation of motion=v=u+at

18=0+6a

=>a=3m/sec sq.

now we have

u=0
v=18

a=3
t=12

we have to find the displaceent(s)

use 2nd equaion of moton

s=ut+1/2at*t

s=0*12+1/2*(3)*12*12=216m

answer=216 m will be displacement after 12 sec

ANSWERED BY MR.BEST

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