Question

A body starts from rest and covers half of the total distance in the last two seconds. What is the total time and the height?

Answer 1

Answer:

Step-by-step explanation:

The distance travelled with constant acceleration in a given time t is, " S = u×t + (1/2)×a×t2 " ,

For first half time, initial speed u=0, hence distance X1 = (1/2)×a×(t/2)2 = (1/8)×a×t2 .................(1)

for second half time, initial speed = a×(t/2), hence distance X2 = a×(t/2)×(t/2) + (1/2)×a×(t/2)2 = (3/8)×a×t2 .............(2)

from (1) and (2), we can write X2 = 3 × X1

Hope it helps you....