Question

A body starts from rest and covers s distance of 10m with an acceleration of 2m's find the speed
after travelling 10m?​

Answer 1

Answer:

speed of the body after covering 10 m.

= 2√10 m/s

Explanlination:

given that,. initial velocity(u) of the body

= 0 m/s

distance travelled(s) = 10 m

acceleration(a) = 2 m/s²

by the equation of motion

v² = u² + 2as

v² = 0² + 2(2)(10)

v² = 40

v = 2√10 m/s

so,

speed of the body after covering 10 m.

= 2√10 m/s

Answer 2

Answer:

Given :-

The body covers the distance (s) = 10 m

Acceleration (a) = 2 m/s

Initial velocity (u) = 0

We need to find the speed of after travelling 10 m

Using the equation of Motion,

v^2 = u^2 + 2as

v^2 = 0^2 + 2×2×10

v^2 = 0 + 40

v^2 = 40

v = 40

v = 2√10 m/s

Therefore, the speed of car after travelling 10 m is 2√10 m/s

Speed :- When a body covers a distance at the rate of metre per second.

Acceleration :- Change in velocity rate with respect time and surrounding.

Distance :- When the body travelled and covered a certain distance.