Physics, asked by kirangan6, 1 year ago

A body starts from rest and has an acceleration of 20cm persecondsquare what is the distance covered by the body in first 8 seconds.

Answers

Answered by Anonymous
13
Hi 
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As We Know , 
S = ut+1/2 at ^2 
Here ,
u = 0 
a = 20 
t = 8 
S= ?
_________________________________________

S =  1/2 X 20 X 64 
S =  640 cm 
S = 6.4 m 
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kirangan6: thanks sahillin
Anonymous: :)
Answered by Anonymous
8
HI there ...

As the body is starting from rest ,

Initial Velocity = u = 0 m/s

Acceleration = a = 20 cm/s²

Time = t = 8 sec

Distance traveled = s

Equation of Motion :

s = ut + 1/2at²

= 0 + 1/2 × 20 × 8 × 8

= 640 cm [ 1 m = 100 cm ]

= 640 /100 m

= 6.4 metre
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