Question

a body starts from rest and is uniformly accelerated.It travels a distance x in t seconds.Show that the distance travelled in the t th second of the motion is =s t th second=(2/t-1/t^2)x

Answer 1

Answer:

let acceleration is a. then

for first x distance. using equation of motion for constant acceleration

v=

2ax

and time taken to cover this distance is T

1

=

a

2x

for second 2x distance

time taken to cover is T

2

=

2ax

2x

then T

2

=

a

2x

for 3rd diatnce of 3x

a

2

=

3x

2ax

. then T

3

=

3

2a

2ax

then total time is T=(

2

3

+1+1)

a

2x

average velocity is

2

7

.

a

2x

6x

. =>V

Av

=

7

6

.

2ax

.

then ration of average velocity to maximum velocity is

7

6

.

Explanation:

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