Question

A body starts from rest and move along a straight line with uniform acceleration a. The distance travelled in the 5th second of its motion is

Answer 1

Answer:

Hence, the distance covered by it in fifth second is 36 m.

Explanation:

hope it's helpful

Answer 2

Answer:

s(5) = 9a/2

Explanation:

To find the distance traveled in the N th second, we use the formula,

s(n) = u + 1/2*a(2n-1)

=>For 5th second, the distance travelled

=> acceleration = a

=> initial velocity = 0 = u

=> s(n) = distance traveled in the nth second.

=> s(5) = 1/2*a(9)

=>s(5) = 9a/2