Physics, asked by binduscorp, 4 months ago

a body starts from rest and moves along a straight line with uniform acceleration A the distance traveled in its 5th second of motion is​

Answers

Answered by Waniiqra1234
0

Answer:

Distance travelled by a body in 'n'th second is

s

n

=u+

2

a

(2n−1)

Distance travelled in 'n' seconds is

s=un+

2

1

an

2

u is zero since the body starts from rest.

s

s

n

=

2

1

an

2

2

a

(2n−1)

Therefore, the ratio =

s

s

n

=

n

2

n

2

1

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