Question

A body starts from rest and moves from uniform acceleration where uniform acceleration is equal to metres per second square and then it travels a distance on 625 find its velocity

Answer 1

Dear Student,

◆ Answer -

v = 50 m/s

● Explanation -

# Given -

u = 0 m/s

s = 625 m

a = 2 m/s^2

# Solution -

Applying Newton's 3rd law of motion -

v^2 = u^2 + 2as

v^2 = 0^2 + 2×2×625

v^2 = 2500

v = 50 m/s

Hence, velocity of the body is 50 m/s.

Thanks dear. Hope this helps you...

Answer 2

Answer:-

Given:-

• Initial velocity (u) = 0 m/s
• Acceleration (a) = 2 m/s²
• Distance (s) travelled = 625 m

To Find:-

Final velocity of the particle.

_______...

We know,

➤ v² - u² = 2as (3rd Eqⁿ of Motion)

Where,

• v = Final Velocity,
• u = Initial Velocity,
• a = Acceleration &
• s = Distance.

➽ v = √2as + u²

➽ v = √2as

[u = 0; 0² = 0.]

Therefore,

v = √2 × (2m/s × s) × 625m

➠ v = √(4m²/s²)(625)

➠ v = 2m/s × 25

[Since 2² = 4 &

(25)² = 625]

➠ v = 50 m/s

Therefore, the final velocity of the particle was 50 m/s.