Physics, asked by veenadevi1811, 7 months ago

a body starts from rest and moves with a constant acceleration of 4 m/s . calculate the velocity acquired by it after it has covered a distance of 8m.

Answers

Answered by Anonymous

Given :

Initial velocity (u) = 0 m/s
Acceleration (a) = 4 m/s
Distance Traveled = 8m

Solution :

Use 3rd equation of motion, as we are provided with the initial velocity, acceleration as well as distance traveled.

➠ v² - u² = 2as

⇒v² - 0² = 2 × 4 × 8

⇒v² - 0 = 8 × 8

⇒v² = 64

⇒v = √(64)

⇒v = 8

$\therefore$ Final Velocity is 8 m/s

_______________________

According to question

Given :-

Initial Velocity of Body=0 m/s

Acceleration of Body =4 m/s square

Distances travelled by Body =8 m.

To find :-

Velocity of body after covered 8m.

Now,

Solution:-

By using Third Law of Motion

$v {}^{2} - u {}^{2} = 2as \\ v {}^{2} - 0 {}^{2} = 2 \times 4 \times 8 \\ v {}^{2} = 64 \\ v = \sqrt{64} \\ v = 8m \: per \: second$

Therefore the required answer will be 8m/s.

hope this answer helps you..

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