Physics, asked by CaptainAmerica7, 1 year ago


A body starts from rest and moves with a uniform acceleration. The ratio of the distance
covered in the nth second to distance covered in n second is
1. (2÷n)-(1÷n^2)
2. (1÷n^2)-(1÷n)
3. (2÷n^2)-(1÷n)
4. (2÷n)+(1÷n^2)​

Answers

Answered by malhijaspal75
1

Answer:

(2n-1)/n^2

hope it will help you....

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Answered by lachry
0

Answer:

2n-1/n^2

Explanation:

find the distance covered in (n-1) seconds (USING EQUATION S=ut+1/2at^2, u will be zero as it starts from rest) and find distance covered in n seconds than subtract both to find distance covered in nth second. then find the ratio of the distances.

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