a body starts from rest and moves with a uniform acceleration of 10m/s2 in a first 10 sec.during the next 10 sec it moves with uniform velocity.calculate the total distance covered by it.
Answers
Answered by
3
First 10seconds -500 next 95total595
Answered by
13
u=initial velocity
v =final velocity
a =acceleration
s =displacement
According to the question
u = 0 m /sec
a =10m /sec ^2
t =10 sec
s =??
now we will apply 2 equation of motion
s =ut +1/2 at^2
s =0 ×10 +1/2 (10 )10^2
s=1/2 ×10×100
s =5×100
s=500 m
for next 10 sec
95m
500+95
595 m
v =final velocity
a =acceleration
s =displacement
According to the question
u = 0 m /sec
a =10m /sec ^2
t =10 sec
s =??
now we will apply 2 equation of motion
s =ut +1/2 at^2
s =0 ×10 +1/2 (10 )10^2
s=1/2 ×10×100
s =5×100
s=500 m
for next 10 sec
95m
500+95
595 m
Similar questions