A body starts from rest and moves with a uniform acceleration of 10ms^(-2) for 5 seconds. During the next 10 seconds it moves with uniform velocity. Find the total distance travelled by the body (Using graphical analysis).
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Answer:
for first 5 second uniform acceleration
so S1=ut+1/2at*2
u=0 (as starting from test)
S1=1/2×10×5×5
S1=125m
finding velocity after 5 second
v²-u²=2as
v²=2×10×125
v= 50
uniform velocity means acceleration is zero
so S2=50×10
so total distance s=625m
hope u understand
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