Question

A body starts from rest and moves with a uniform acceleration of
$m/ {s}^{2}$
- until it travels a distance of 625 m .Find its velocity.​

Answer 1

From the question a graph is drawn above,

Area of v−t graph⟹ distance travelled

v

avg

=

t

1

+t

2

+t

3

8s

2

1

v

m

×t

1

=s

t

1

=

v

m

2s

t

2

×v

m

=2s

t

2

=

v

m

2s

2

1

×t

3

×v

m

=5s

t

3

=

v

m

10s

v

avg

=

v

m

2s

+

v

m

2s

+

v

m

10s

8s

v

m

v

avg

=

7

4

Answer 2

Answer:

Given,

$Initial Velocity\: u = 0m/s$

Final Velocity, v =?

$Acceleration = 2m/ {s}^{2} \\ distance = s = 625m$

By the third equation of motion

${v}^{2} - {u}^{2} = 2as \\ {v}^{2} - 0 = 2 \times 2 \times 625 \\ {v}^{2} = 2500 \\ v = 50m/s$

Final velocity of the body is 50m/s