Question

A body starts from rest and moves with a uniform acceleration of 2 m/s² until it travels a distance of 625 m . Find its velocity.
250 m/s
- 50. m/s
50 m/s
2500 m/s

Answer 1

Given:

• Acceleration,a = 2 m/s²

• Distance, s = 625 m

• Initial velocity,u = 0 m/s [ A body starts from rest ]

To be calculated:

Calculate the final velocity ( v ) of given body?

Formula used:

v² = u² + 2as

Solution:

We know the initial velocity, acceleration and distance. so, Final velocity can be calculated by using the equation:

v² = u² + 2as

★ Putting the value in the third equation of motion, we get

v² = 0² + 2 × 2 × 625

v² = 0 + 4 × 625

v² = 2500

v = √2500

v = 50 m/s

Thus,the final velocity of given body is 50 m/s.

Answer 2

GIVEN:

• Initial Velocity (u) = 0
• Acceleration (a) = 2 m/s²
• Distance (s) = 625 m

TO FIND:

• What is the velocity of the body ?

SOLUTION:

We have given that, a body starts from rest and moves with a uniform acceleration of 2 m/s² until it travels a distance of 625 m

To find the velocity of the body, we use the third equation of motion

$\large\bf{\star \: v^2 = u^2 + 2as \: \star}$

According to question:-

On putting the given values in the equation, we get

$\rm{\dashrightarrow v^2 = (0)^2 + 2 \times 2 \times 625 }$

$\rm{\dashrightarrow v^2 = 0 + 4 \times 625 }$

$\rm{\dashrightarrow v^2 = 2500 }$

$\rm{\dashrightarrow v = \sqrt{2500} }$

$\large\bf{\dashrightarrow \star \: v = 50 \: m/s \: \star}$

❝ Hence, the velocity of the body is 50 m/s. ❞

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✰ Extra Information ✰

➲ First equation of motion = v = u + at

➲ Second equation of motion = s = ut + 1/2 at²