Question

A body starts from rest and moves with a uniform acceleration of 5 m/s² until it travels a distance of 100 m . Find its velocity

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Answer 1

Given :-

★ Acceleration, a = 5 m/s²

★ Initial velocity, u = 0 ( As body starts from rest)

★ Distance traveled, s = 100 m

To Find :-

★ Final velocity of the body

Solution :-

According to the question :-

To find final velocity, we have to use 3rd equation of motion.

We know, 3rd equation of motion

$\sf v^2-u^2=2as$

Here,

v = Final velocity

u = Initial velocity

a = Acceleration

s = Distance

Now, put the given values

⟹ v = 2 × 5 × 100 + (0)

⟹ v = 31.62 m/s ( Approx)

Hence, the final velocity of the body is

= 31.62 m/s

Extra Information :-

☞ Force = mass × acceleration

☞ v = u + at

{ 1st equation of motion}

☞ s = ut + ½ at²

{ 2nd equation of motion}

☞ v² = u² + 2as

{ 3rd equation of motion}

☞ Pressure = Force/Area

Answer 2

Given ,

Inital velocity (u) = 0 m/s

Acceleration (a) = 5 m/s²

Displacement (s) = 100 m

We know that , the Newton's third equation of motion is given by

$\boxed{ \sf {(v)}^{2} - {(u)}^{2} = 2as}$

Thus ,

(v)² - (0)² = 2 × 5 × 100

(v)² = 10 × 1000

v = √1000

v = 31.6 m/s

Therefore ,

The final velocity is 31.6 m/s