A body starts from rest and moves with a uniform acceleration of 2 m/s 2 until it travels a distance of 625 m. Find its velocity. Also find the time taken by the body to travel this distance.
Answers
Answered by
0
Explanation -
initial velocity (u) = 0 m/s
acceleration (a)=2 m/s^2
distance (d) = 625 m
time (t)= ?
now,
v^2 = u^2 + 2as
v^2 = 0 + 2 x 2 x 625
v^2 = 2500
v = under root 2500
v = 50 m/s
then,
a = v-u / t
or , 2 = 50 - 0 / t
or , 2t = 50
or , t = 50 / 2
therefore, t = 25 sec
Hope this will help you
Answered by
2
Answer:
Time = 25second
The last velocity is = 50m/s
Explanation:
Here,
given that,
- the begining velocity,u=0m/s
- the acceleration,a=2ms^-2
- the distance,s=625m.
here,
- s=ut+1/2at^-2
- s=1/2×2t^2
- s=t^2
- t^2=625
- t=√625
- t=25s.
so,the time is 25s.
then,
- v=u+at
- v=0+2×25
- v=50m/s
so,the last velocity is,v=50m/s.
Hope its help you,Thanks.
Please mark as a brainlist answer.
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