Physics, asked by palakchughgames, 1 month ago


A body starts from rest and moves with a uniform acceleration of 2 m/s 2 until it travels a distance of 625 m. Find its velocity. Also find the time taken by the body to travel this distance.

Answers

Answered by AadityaJha01
0

Explanation -

initial velocity (u) = 0 m/s

acceleration (a)=2 m/s^2

distance (d) = 625 m

time (t)= ?

              now,

v^2 = u^2 + 2as

v^2 = 0 + 2 x 2 x 625

v^2 = 2500

v = under root 2500

v = 50 m/s

then,

a = v-u / t

or , 2 = 50 - 0 / t

or , 2t = 50

or , t = 50 / 2

therefore, t = 25 sec

Hope this will help you

Answered by naymul504
2

Answer:

Time = 25second

The last velocity is = 50m/s

Explanation:

Here,

given that,

  1. the begining velocity,u=0m/s
  2. the acceleration,a=2ms^-2
  3. the distance,s=625m.

here,

  • s=ut+1/2at^-2
  • s=1/2×2t^2
  • s=t^2
  • t^2=625
  • t=√625
  • t=25s.

so,the time is 25s.

then,

  • v=u+at
  • v=0+2×25
  • v=50m/s

so,the last velocity is,v=50m/s.

Hope its help you,Thanks.

Please mark as a brainlist answer.

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