Question

A body starts from rest and moves with a uniform acceleration. The ratio of the distance covered in the nth second to distance covered in n seconds is​

Answer 1

ANSWER

Distance travelled by a body in 'n'th second is

Sn = u + a/2 (2n-1)

Distance travelled in 'n' seconds is

s = un + 1 / 2 an^ 2

u is zero since the body starts from rest

Sn = a (2n-1)

S 2

1 an ^ 2

2

Therefore, the ratio = Sn = 2 - 1

S n n^2

MORE INFORMATION:-

• Acceleration is the rate of change of the velocity of an object with respect to time.

• Accelerations are vector quantities (in that they have magnitude and direction). The orientation of an object's acceleration is given by the orientation of the net force acting on that object.