Question

A body starts from rest and moves with a uniform acceleration of 5m/s2 for 8 seconds. from that time the ceases . find the distance covered in 12sec starting from rest

Answer 1

So,

Initially the body was at rest

So,

u=0

Now, it accelerates for 8 sec with a=5 m/s²

So,

Distance covered is

s=ut + 1/2 × at²

s=1/2 × 5 ×64

s=32 × 5

s=160 m

Now,

Velocity after 8 sec

v= u+ at

v= 0 + (5)×8

v= 40 m/s

So,

distance covered after 8 sec upto next (12-8) 4 sec is

d= 4 × 40

d=160 m

so,

Total distance covered for 12 sec is

160 + 160

=320 m

So,

Th body will cover a distance of 320 m

Answer 2

Answer:the ans is 320

Explanation: hope it helps you