a body starts from rest and moves with a uniform acceleration of 10 m to the power of -2 in the first 10 seconds during the next 10 seconds it moves with the maximum velocity at 10:00 the total displacement of the body is
Answers
Answered by
1
Use the formula
S = ut + 1/2at^2
u = 0, a = 10m/s^2 and t = 10s
Then s = 0*10 + 1/2*10*10^2
= 0 + 500 = 500m
So distance travelled in first 10s = 500m
Now its final velocity
v = u + at
v = 0 + 10*10 = 100m/s
Then,
S = v*t = 100*10 = 1000m
So the total distance travelled in 20s
1000+500 = 1500m
Here is ur answer!!
S = ut + 1/2at^2
u = 0, a = 10m/s^2 and t = 10s
Then s = 0*10 + 1/2*10*10^2
= 0 + 500 = 500m
So distance travelled in first 10s = 500m
Now its final velocity
v = u + at
v = 0 + 10*10 = 100m/s
Then,
S = v*t = 100*10 = 1000m
So the total distance travelled in 20s
1000+500 = 1500m
Here is ur answer!!
rakshithreddy:
next question a truck is moving with a velocity of 10 M ^ -1 on a straight road as the drivers observes a single before them him he applied brakes which dictionary truck at 5 M ^ -2 as a distance 17 m from the moment the driver observed the signal reaction time for the driver is
which decelerates
Sorry now I am busy
will solve it later...
bye
ok send your whats app number i will send d oughts through photos
ok
9534968881
bye
now free or not
Similar questions