Question

A body starts from rest and moves with a uniform acceleration of 10ms^-1 in the first 10seconds. During the next 10seconds. It moves with the maximum velocity attained. The total displacement of the body is

Answer 1

Using the above two equations,
Where
Vo = initial velocity = 0 m/s
V = final velocity = maximum velocity attained
a = acceleration = 10 m/s^2
t = time

Now using the first equation we get,
d = 0 + (1/2)(10)(10)^2
d = 500 m

Using second equation we can find final velocity,

V = 0 + (10)(10)
V = 100 m/s

During the next 10 seconds speed will remain 100 m/s only, so using V = d/t we get,

d' = V t
d' = (100)(10)
d' = 1000 m

Total displacement = d + d' = 500 + 1000 = 1500 m