Question

A body starts from rest and moves with an acceleration of 10 m/sq. s and attains a velocity of 50 m/s. Calculate the distance travelled by the body during this time.​​​

Answer 1

Answer:

The initial velocity travelled is 625m

The accleration is α=10m/s

2

The time is t=5s

Apply the equation of motion

v=u+at

The velocity is v=0+10.5=50m/s.

The distance travelled in the first 5s is

s=ut+

2

1

at

2

=0.5+

2

1

.10.5

2

=125m

Thedistancetravelledinthefollowing10sis

s

1

=ut

1

=50.10=500m

Thetotaldistancetravelledis

d=s+s

1

=125+500=625m