Question

A body starts from rest and moves with an acceleration of 2 metre per second square. Find the distance covered by body in the 10th second of its motion

Answer 1

Answer:

Distance travelled in 10th seconds

= 19 meter

Step by step explanations :

Given that,

A body starts from rest and moves with an acceleration of 2 m/s²

here,

Initial velocity of the body = 0 m/s

[because it was initially at rest]

Acceleration of the body = 2 m/s²

To find,

distance covered by body in the 10th second of its motion

We know that distance travelled in nth seconds

= u + a/2(2n - 1)

let the distance covered in 10th seconds be S10

here,

n = 10 s

initial velocity(u) = 0 m/s

acceleration(a) = 2 m/s²

putting the values

S10 = 0 + 2/2(2(10) - 1)

= 20 - 1

S10 = 19

so,

Distance travelled in 10th seconds

= 19 meter

Answer 2

Answer

Explanation

Given :-

A body starts from rest

So,

u (initial velocity) = 0

acceleration = 2m/s²

To find :-

Distance travelled in 10 seconds

Solution :

We know that distance travelled in nth second =

Sn = u + a/2(2n-1)

____________________[Put values]

$\large{\boxed{n \: = \: 10}}$

S10 = 0 + 2/2(2*10-1)

S10 = 20-1

S10 = 19

S10 = 19 m

____________________

So, distance travelled in 10th second is 19 m.