Question

a body starts from rest and moves with an acceleration of 2m/ s²
find the distance travelled by the body in the 5th second ​

Answer 1

Answer:

as body starts from rest so u-0 m/s

a-2m/s² to find- distance in 5th sec

Sn= u+1/2a(2n-1)

where n is second no. (here its 5th sec)

on putting values...

S5=

$0 + \frac{1}{2} \times 2(10 - 1) \\ = 9 \: metres$

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