Question

a body starts from rest and moves with an acceleration of of 2m/ s find the distance covered by the body in the 10th second of its motion​

Answer 1

Explanation:

s=ut+½at²

a=v-u/t

=0.2m/s²

s=10m

Answer 2

Acceleration = v-u/t = 2 m/s^2
u(initial velocity)= 0 m/s
v(final velocity) = unknown
t(time) = 1/10 seconds

v-0/1/10 = 2
10v = 2
= v = 2/10
= 1/5 m/s