a body starts from rest and moves with constant acceleration .the ratio of the distance covered in nth second to the distance covered in n seconds is
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hey,
your answer is below...
Distance covered in nth second is given by
sn = u + a/2(2n-1)
where u – intial velocity and a – acceleration
Distance covered in t seconds is given by
s = ut + a/2(t2)
But, here u = 0
So,sn = a/2(2n-1) and s = a/2(t2)
I hope this information is useful for you.
your answer is below...
Distance covered in nth second is given by
sn = u + a/2(2n-1)
where u – intial velocity and a – acceleration
Distance covered in t seconds is given by
s = ut + a/2(t2)
But, here u = 0
So,sn = a/2(2n-1) and s = a/2(t2)
I hope this information is useful for you.
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