a body starts from rest and moves with the uniform acceleration of 3 meter per second square what will be the velocity at end of 15 second
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Using the equations of motion,
s = ut+1/2 at^2
v = u + at,
where
s = displacement,
u = initial velocity
a = acceleration
t = time
Using the first equation s = ut+1/2 at^2
1ooom = 0(t) +1/2(a)(100s)^2
Solving for a, we obtain:
a = 0.2m/s^2
Using the other equation of motion:
v = u + at,
v = 0 + (0.2m/s^2)(100s)
v = 20m/s
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