a body starts from rest and moves with uniform acceleration of 4 m/s^2 until it
travel distance of 800 M find the final velocity
Answers
Answered by
4
hey ur answer
A=4 m/s2
s=800m
u=0 m/s
s=ut+ 1/2 at2
800=0+1/2*4*t2
800=2t2
400=t2
t=20 s
a=(v-u)/t
4=v-0/20
80=v
v=80 m/s
thanks follow me
A=4 m/s2
s=800m
u=0 m/s
s=ut+ 1/2 at2
800=0+1/2*4*t2
800=2t2
400=t2
t=20 s
a=(v-u)/t
4=v-0/20
80=v
v=80 m/s
thanks follow me
Answered by
6
heya friend!!☺☺
here's your answer!!☺☺
Given,
Initial velocity, u = 0 m / s
Acceleration, a = 4 m/s2
Distance, s = 800 m
Final velocity = ?
Using the 3rd equation of motion, which is:,
we get
2as=v²-u²
v2 - 0= 2(4)(800)
V2 = 6400
Therefore, v = 80
Therefore, the final velocity = 80 m/s
hope it helps you!!☺☺
here's your answer!!☺☺
Given,
Initial velocity, u = 0 m / s
Acceleration, a = 4 m/s2
Distance, s = 800 m
Final velocity = ?
Using the 3rd equation of motion, which is:,
we get
2as=v²-u²
v2 - 0= 2(4)(800)
V2 = 6400
Therefore, v = 80
Therefore, the final velocity = 80 m/s
hope it helps you!!☺☺
foradityamp96pjw:
hi
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