a body starts from rest and moves with uniform acceleration of 5m/s for 8 seconds. from that time the acceleration ceases. find the distance covered in 12 seconds starting from rest
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By the application of Second equation of motion,
S=ut+1/2at²
Since, initial velocity 'u' =0
=> S= 0x12+1/2 x 5 x (12)²
=> S= 0+1/2 x 5 x 144
=> S= 5 x 72
=> S= 360m
Hope it helps you......
S=ut+1/2at²
Since, initial velocity 'u' =0
=> S= 0x12+1/2 x 5 x (12)²
=> S= 0+1/2 x 5 x 144
=> S= 5 x 72
=> S= 360m
Hope it helps you......
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