Question

A body starts from rest and moves with uniform acceleration 2m/second square find out the distance covered in 5 second s=ut+1/2at square , u=0,t=5,a=2m / second s=?

Who will say the correct answer i will make them as brilliant ​

Answer 1

Answer:

Correct option is A)

u=0,a=2m/s

2

,t=2s

Putting the values in S=ut+

2

1

at

2

S=0×2+

2

1

×2×2

2

S=4m

Explanation:

hope it helps you bro have a great day

Answer 2

Explanation:

u=0m/s

a =2m/s^2

t=5 sec

distance=?

using equation s=1/2at^2

s=1/2×2×5×5

s=1/2×50

s=25m