A body starts from rest and moves with uniform acceleration. If it acquire a velocity of 80 m/s in 20 second,find the distance covered by it in 20 second
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Question :
A body starts from rest and moves with uniform acceleration. If it acquire a velocity of 80 m/s in 20 seconds,find the distance covered by it in 20 second .
Here we have :
- InitiaI veIocity (u) = 0 m/s [As it starts from rest]
- FinaI veIocity (v) = 80 m/s
- Time (t) = 20 s
So we have to find distance covered in 20 seconds.
For that we wiII use 1st equation of motion at first to find acceIeration (a) :
⇔ v = u + at
⇒ 80 = 0 + a × 20
⇒ 80 = 20a
⇒ a = 80/20
⇒ a = 4 m/s²
Now we wiII use 2nd equation of motion to find distance covered :
⇔ s = ut + 1/2 at²
⇒ s = 0 × 20 + 1/2 × 4 × (20)²
⇒ s = 0 + 2 × 400
⇒ s = 0 + 800
⇒ s = 800 m
Therefore,
Distance covered by body = 800 m
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Vf=vi+at
a=(vf-vi)/t=(80-0)/20=4m/s.s
Now using 3rd equation of motion,
2aS=(vf.vf)-(vi.vi)
2(4)S=(80×80)-(0×0)
8S=6400
S=6400/8=800m