A body starts from rest and moves with uniform acceleration. If it acquire a velocity of 80 m/s in 20 second,find the distance covered by it in 20 second
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initial velocity=0
velocity=80m/s
time=20s
acc=80/20= 4m/s
so s=ut+1/2at²
on solving s=800m
velocity=80m/s
time=20s
acc=80/20= 4m/s
so s=ut+1/2at²
on solving s=800m
mullaanis22:
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Answered by
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Intial velocity=0m/s
Final velocity=80m/s
Time=20 seconds
Accerlation=v=u+at
=80=0+a×20
80/20=
accerlation=4m/s
From equation of motion.
V²-u²=2as
80²-0²=2×4×s
6400=8s
s=6400/8
s=800
Distance=800m
Final velocity=80m/s
Time=20 seconds
Accerlation=v=u+at
=80=0+a×20
80/20=
accerlation=4m/s
From equation of motion.
V²-u²=2as
80²-0²=2×4×s
6400=8s
s=6400/8
s=800
Distance=800m
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