Physics, asked by neevenemmanuel, 10 months ago

A body starts from rest and picks up a velocity of 15 m/s in 3 s. The acceleration in km/h2 is

Answers

Answered by helnamariyamjames
0

Answer:

HERE IS YOUR ANSWER

Explanation:

initial velocity ( u) = 0m/sec

final. velocity ( v ) = 15 m/sec

time ( t) = 3 sec

acceleration =v- u / t

= 15 - 0/3

= 15 /3

= 5 m/sec ²

= 18 km/ hr

HOPE IT HELPS YOU

Answered by jimmykhiangte1
0

Answer:

18Km/H²

Explanation:

Acceleration is as we know product of velocity per time.

Given from the question we have, velocity is 15m per sec.

So acceleration is 3 metre per sec.

As a=v/t ,also, v=d/t, so a = d×t/t

In one minute we have 60 secs so in 1 minute, the velocity is 900m/60s

In one hour, we have 60 mins, the velocity is 54,000m/3600s

Given acceleration is 3s, converting in hour it is 3/3600s.

Therefore,

a 3s= 15m/s or

a 3/3600s = 54,000/3600 m/s

a = 54,000/3600 ÷ 3/3600 m/s÷1/s

using cross multiplication, we have

a= 54,000× 3600 ÷ 3600 ×3 m×1/s×s

cutting 3600s or 1H each assume s² to H², we have,

a=54000÷3 m/H²

a= 18,000m/H² or 18thousand(kilo)metres per hour square.

Therefore a=18km/h²

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