Question

A body starts from rest and rolls down a hill with a constant acceleration.if it travels 400m in 20 seconds,calculate the force acting on the body if its mass is 10 kg

Answer 1

Answer:

U=0m

s=400m

t=20sec

m=10kg

a=?

f=?

s=ut+1/2at^2

400=0×20+1/2a×20^2

400=0+200a

400=200a

then,a=400/200

a=2m/sec^2

f=ma

f=10×2

f=20N

Answer 2

Answer:

20 N

Explanation:

Here we are given that:-

s=400m

u= 0 m/s

t= 20s

m= 10 kg

By using 2nd Kinematic Equation we will find acceleration.

s=ut+1/2 at^2

400= 0*20 +1/2*a*(20)^2

400= 400a/2

400= 200a

a= 400/200

= 200 m/s^2

Force = mass * acceleration

= 10*2

= 20N

Hope my answer will help you please mark me brainliest