a body starts from rest and then covers 30 meter qn 5 second. calculate the increase in the velocity per second
Answers
Answered by
1
Hey dear here is your answer........
According to question:-
u=0m/sec
s=30m
t=5sec
S=ut+1/2at^2
30=0+25a
a=5/6m/s^2
v=u+at
v=5/6×5
v=25m/s....
hope it helps u!! hi
According to question:-
u=0m/sec
s=30m
t=5sec
S=ut+1/2at^2
30=0+25a
a=5/6m/s^2
v=u+at
v=5/6×5
v=25m/s....
hope it helps u!! hi
helpme10:
pardon !!!
Answered by
0
distance(s)=30m
timetaken(t)=5sec
Now,
v=s/t=30/5=6 m/s
timetaken(t)=5sec
Now,
v=s/t=30/5=6 m/s
Similar questions