Physics, asked by syedsaifali2311, 11 months ago

a body starts from rest and travel in straight line with the uniform acceleration of 5 metre per second square for 5 second what is the velocity and distance travel in this time​

Answers

Answered by BrainlyConqueror0901
29

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\therefore{Final\:velocity=25\:m/s}}}

\green{\tt{\therefore{Distance\:travlled=62.5\:m}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

 \green{\underline \bold{Given:}} \\  \tt:  \implies Acceleration(a) = 5 \:  {m/s}^{2}  \\  \\  \tt:  \implies Time(t) = 5 \: sec \\  \\  \red{\underline \bold{To \: Find:}}\\  \tt:  \implies Final \: velocity(v ) = ? \\  \\ \tt:  \implies Distance \: travelled(s ) = ?

• According to given question :

 \tt \circ \: Initial \: velocity = 0 \: m/s  \\  \\ \bold{As \: we \: know \: that} \\  \tt:  \implies v = u + at \\  \\ \tt:  \implies v = 0 + 5 \times 5 \\  \\ \tt:  \implies v = 5 \times 5 \\  \\  \green{\tt:  \implies v = 25 \: m/s} \\  \\  \bold{As \: we \: know \:that} \\ \tt:  \implies s =  ut + \frac{1}{2} a {t}^{2}  \\  \\ \tt:  \implies s = 0 \times 5 +  \frac{1}{2}  \times 5 \times  {5}^{2}  \\  \\ \tt:  \implies s = 0 +  \frac{1}{2}  \times 5 \times 25 \\  \\ \tt:  \implies s =  \frac{125}{2}  \\  \\  \green{\tt:  \implies s = 62.5 \: m}

Answered by Anonymous
82

Answer:

Given:

• A body starts from rest and travel in straight line with the uniform acceleration of 5 metre per second square for 5 second.

Find:

• What is the final velocity and distance travel in this • time.

According to the question:

• 5 m/s = Acceleration.

• 5 second = Time.

• Infinity velocity is equal to 0 m/s.

Know terms:

• (v) = velocity.

• (u) = Initial velocity.

• (a) = Acceleration.

• (t) = Time.

• (s) = Speed.

Using formula:

• v = u + at [ for case (1) ]

• s = ut + ½ at² [ for case (2) ]

Using the above formula, writing the calculations as follows:

Finding velocity:

⇒ v = 0 + 5 × 5

⇒ v = 5 × 5

v = 25 m/s - Case (1) [ Velocity ]

Finding distance travelled:

⇒ s = 0 × 5 + ½ × 5 × 5²

⇒s = 0 + ½ × 5 × 25

⇒ s = 125/2 = 62.5

s = 62.5 - Case (2) [ Speed ]

Therefore, 25 m/s is the final velocity and 62.5 is the speed.


BrainlyConqueror0901: fantastic nayan bhai : )
Similar questions