Question

A body starts from rest and travels 270m in 3 seconds. What will be its velocity at the end of 10 seconds?

The answer is 600 m/sec

Kindly give complete solution​

Answer 1

hey mate here is your answer

Here the main thing is uniform acceleration which means that "a" would be constant such that acceleration after 3s would be equal to acceleration after 10 s so from 1st case we will find the acceleration from 2nd equation of motion. i.e s=ut + 1/2 at^{2} from this equation we will find 

   1/2 at2 = s-ut 

  a= 2(s-ut)/t2

  here initial speed u=0 so ut = 0

  a= 2*270/3*3 

  a = 60m/s2 - (1)

  Now we know that v= u+at

from eqn 1 a= 60m/s2

 so here v= 0+ 60*10

 v=600m/s

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