Question

A body starts from rest and travels with an acceleration of 2 m/s2 . After t seconds itsvelocity is 10 m/s . Then t is

Answer 1

Answer:

5sec

Explanation:

a=2m/s^2

u=0m/s

time=t sec

v=10 m/s

as we know that

a=v-u/t

2=10-0/t

using cross multiplication

2t=10-0

2t=10

substituting 2 to the right side of equal to

t=10/2

on dividing

t=5sec

Answer 2

Given:

Body starts from rest, so initial velocity (u) = 0 $m/s$  

Acceleration of the body (a) = 2 $m/s^{2}$  

Final velocity (v) = 10 $m/s$  

To find: Time taken (t) for the body to go from initial velocity to final velocity

Calculation:

First equation of motion is used for calculating the time duration (t).  

Let the body start with velocity u to arrive at final velocity v by moving with an acceleration of a in time t, then  

$a = (v-u)/t\\t = (v-u)/a\\t = (10 - 0)/2 s\\t = 5 s$

So, the time taken for the body to accelerate from rest to final velocity 10m/s is 5 seconds.